3(X-2)+4(X-3)=7(X-2)

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Solution for 3(X-2)+4(X-3)=7(X-2) equation: 


Simplifying
3(X + -2) + 4(X + -3) = 7(X + -2)

Reorder the terms:
3(-2 + X) + 4(X + -3) = 7(X + -2)
(-2 * 3 + X * 3) + 4(X + -3) = 7(X + -2)
(-6 + 3X) + 4(X + -3) = 7(X + -2)

Reorder the terms:
-6 + 3X + 4(-3 + X) = 7(X + -2)
-6 + 3X + (-3 * 4 + X * 4) = 7(X + -2)
-6 + 3X + (-12 + 4X) = 7(X + -2)

Reorder the terms:
-6 + -12 + 3X + 4X = 7(X + -2)

Combine like terms: -6 + -12 = -18
-18 + 3X + 4X = 7(X + -2)

Combine like terms: 3X + 4X = 7X
-18 + 7X = 7(X + -2)

Reorder the terms:
-18 + 7X = 7(-2 + X)
-18 + 7X = (-2 * 7 + X * 7)
-18 + 7X = (-14 + 7X)

Add '-7X' to each side of the equation.
-18 + 7X + -7X = -14 + 7X + -7X

Combine like terms: 7X + -7X = 0
-18 + 0 = -14 + 7X + -7X
-18 = -14 + 7X + -7X

Combine like terms: 7X + -7X = 0
-18 = -14 + 0
-18 = -14

Solving
-18 = -14

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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