3(X+2)=7x-8+4x

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Solution for 3(X+2)=7x-8+4x equation: 



3(X+2)=7X-8+4X

We move all terms to the left:

3(X+2)-(7X-8+4X)=0

We add all the numbers together, and all the variables

3(X+2)-(11X-8)=0

We multiply parentheses

3X-(11X-8)+6=0

We get rid of parentheses

3X-11X+8+6=0

We add all the numbers together, and all the variables

-8X+14=0

We move all terms containing X to the left, all other terms to the right

-8X=-14

X=-14/-8

X=1+3/4

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