3(X+1)=6+2(m-2)

Solution for 3(X+1)=6+2(m-2) equation:

3(X+1)=6+2(X-2)

We move all terms to the left:

3(X+1)-(6+2(X-2))=0

We multiply parentheses

3X-(6+2(X-2))+3=0


We calculate terms in parentheses: -(6+2(X-2)), so:

6+2(X-2)

determiningTheFunctionDomain
2(X-2)+6

We multiply parentheses

2X-4+6

We add all the numbers together, and all the variables

2X+2

Back to the equation:

-(2X+2)


We get rid of parentheses

3X-2X-2+3=0

We add all the numbers together, and all the variables

X+1=0

We move all terms containing X to the left, all other terms to the right

X=-1