3(X+1)+4=2(x-2)+20

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Solution for 3(X+1)+4=2(x-2)+20 equation: 



3(X+1)+4=2(X-2)+20

We move all terms to the left:

3(X+1)+4-(2(X-2)+20)=0

We multiply parentheses

3X-(2(X-2)+20)+3+4=0



We calculate terms in parentheses: -(2(X-2)+20), so:

2(X-2)+20

We multiply parentheses

2X-4+20

We add all the numbers together, and all the variables

2X+16

Back to the equation:

-(2X+16)



We add all the numbers together, and all the variables

3X-(2X+16)+7=0

We get rid of parentheses

3X-2X-16+7=0

We add all the numbers together, and all the variables

X-9=0

We move all terms containing X to the left, all other terms to the right

X=9

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