3(B+2)+2B=41

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Solution for 3(B+2)+2B=41 equation:


Simplifying
3(B + 2) + 2B = 41

Reorder the terms:
3(2 + B) + 2B = 41
(2 * 3 + B * 3) + 2B = 41
(6 + 3B) + 2B = 41

Combine like terms: 3B + 2B = 5B
6 + 5B = 41

Solving
6 + 5B = 41

Solving for variable 'B'.

Move all terms containing B to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + 5B = 41 + -6

Combine like terms: 6 + -6 = 0
0 + 5B = 41 + -6
5B = 41 + -6

Combine like terms: 41 + -6 = 35
5B = 35

Divide each side by '5'.
B = 7

Simplifying
B = 7

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