3(B+1)=4(B-5)

Solution for 3(B+1)=4(B-5) equation:

Simplifying
3(B + 1) = 4(B + -5)

Reorder the terms:
3(1 + B) = 4(B + -5)
(1 * 3 + B * 3) = 4(B + -5)
(3 + 3B) = 4(B + -5)

Reorder the terms:
3 + 3B = 4(-5 + B)
3 + 3B = (-5 * 4 + B * 4)
3 + 3B = (-20 + 4B)

Solving
3 + 3B = -20 + 4B

Solving for variable 'B'.

Move all terms containing B to the left, all other terms to the right.

Add '-4B' to each side of the equation.
3 + 3B + -4B = -20 + 4B + -4B

Combine like terms: 3B + -4B = -1B
3 + -1B = -20 + 4B + -4B

Combine like terms: 4B + -4B = 0
3 + -1B = -20 + 0
3 + -1B = -20

Add '-3' to each side of the equation.
3 + -3 + -1B = -20 + -3

Combine like terms: 3 + -3 = 0
0 + -1B = -20 + -3
-1B = -20 + -3

Combine like terms: -20 + -3 = -23
-1B = -23

Divide each side by '-1'.
B = 23

Simplifying
B = 23