3(9x-4x)+8(3x+4)=11

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Solution for 3(9x-4x)+8(3x+4)=11 equation: 



3(9x-4x)+8(3x+4)=11

We move all terms to the left:

3(9x-4x)+8(3x+4)-(11)=0

We add all the numbers together, and all the variables

3(+5x)+8(3x+4)-11=0

We multiply parentheses

15x+24x+32-11=0

We add all the numbers together, and all the variables

39x+21=0

We move all terms containing x to the left, all other terms to the right

39x=-21

x=-21/39

x=-7/13

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