3(9x-2)+5x-16=7(2x-5)+9x-3

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Solution for 3(9x-2)+5x-16=7(2x-5)+9x-3 equation: 



3(9x-2)+5x-16=7(2x-5)+9x-3

We move all terms to the left:

3(9x-2)+5x-16-(7(2x-5)+9x-3)=0

We add all the numbers together, and all the variables

5x+3(9x-2)-(7(2x-5)+9x-3)-16=0

We multiply parentheses

5x+27x-(7(2x-5)+9x-3)-6-16=0



We calculate terms in parentheses: -(7(2x-5)+9x-3), so:

7(2x-5)+9x-3

We add all the numbers together, and all the variables

9x+7(2x-5)-3

We multiply parentheses

9x+14x-35-3

We add all the numbers together, and all the variables

23x-38

Back to the equation:

-(23x-38)



We add all the numbers together, and all the variables

32x-(23x-38)-22=0

We get rid of parentheses

32x-23x+38-22=0

We add all the numbers together, and all the variables

9x+16=0

We move all terms containing x to the left, all other terms to the right

9x=-16

x=-16/9

x=-1+7/9

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