3(9x+3)+13x=1/4(8x-12)+62x

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Solution for 3(9x+3)+13x=1/4(8x-12)+62x equation: 



3(9x+3)+13x=1/4(8x-12)+62x

We move all terms to the left:

3(9x+3)+13x-(1/4(8x-12)+62x)=0



Domain of the equation: 4(8x-12)+62x)!=0

x∈R



We add all the numbers together, and all the variables

13x+3(9x+3)-(1/4(8x-12)+62x)=0

We multiply parentheses

13x+27x-(1/4(8x-12)+62x)+9=0

We multiply all the terms by the denominator


13x*4(8x-12)+62x)+27x*4(8x-12)+62x)-(1+9*4(8x-12)+62x)=0

Wy multiply elements

52x^2(8+62x)+27x*4(8x-12)+62x)-(1+9*4(8x-12)+62x)=0

We add all the numbers together, and all the variables

52x^2(62x+8)+27x*4(8x-12)+62x)-(1+9*4(8x-12)+62x)=0

Wy multiply elements

52x^2(62x+8)+108x^2(8+62x)-(1+36x(8+62x)=0



We calculate terms in parentheses: -(1+36x(8+62x), so:

1+36x(8+62x

determiningTheFunctionDomain
36x(8+62x+1

Back to the equation:

-(36x(8+62x+1)



We add all the numbers together, and all the variables

52x^2(62x+8)+108x^2(62x+8)-(36x(62x+9)=0



We calculate terms in parentheses: -(36x(62x+9), so:

36x(62x+9





We calculate terms in parentheses: -(36x(62x+9), so:

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