3(9-a)=2(a+3)+16a

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Solution for 3(9-a)=2(a+3)+16a equation: 



3(9-a)=2(a+3)+16a

We move all terms to the left:

3(9-a)-(2(a+3)+16a)=0

We add all the numbers together, and all the variables

3(-1a+9)-(2(a+3)+16a)=0

We multiply parentheses

-3a-(2(a+3)+16a)+27=0



We calculate terms in parentheses: -(2(a+3)+16a), so:

2(a+3)+16a

We add all the numbers together, and all the variables

16a+2(a+3)

We multiply parentheses

16a+2a+6

We add all the numbers together, and all the variables

18a+6

Back to the equation:

-(18a+6)



We get rid of parentheses

-3a-18a-6+27=0

We add all the numbers together, and all the variables

-21a+21=0

We move all terms containing a to the left, all other terms to the right

-21a=-21

a=-21/-21

a=1

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