3(8z-1)+4=6(4z-3)+19

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Solution for 3(8z-1)+4=6(4z-3)+19 equation:


Simplifying
3(8z + -1) + 4 = 6(4z + -3) + 19

Reorder the terms:
3(-1 + 8z) + 4 = 6(4z + -3) + 19
(-1 * 3 + 8z * 3) + 4 = 6(4z + -3) + 19
(-3 + 24z) + 4 = 6(4z + -3) + 19

Reorder the terms:
-3 + 4 + 24z = 6(4z + -3) + 19

Combine like terms: -3 + 4 = 1
1 + 24z = 6(4z + -3) + 19

Reorder the terms:
1 + 24z = 6(-3 + 4z) + 19
1 + 24z = (-3 * 6 + 4z * 6) + 19
1 + 24z = (-18 + 24z) + 19

Reorder the terms:
1 + 24z = -18 + 19 + 24z

Combine like terms: -18 + 19 = 1
1 + 24z = 1 + 24z

Add '-1' to each side of the equation.
1 + -1 + 24z = 1 + -1 + 24z

Combine like terms: 1 + -1 = 0
0 + 24z = 1 + -1 + 24z
24z = 1 + -1 + 24z

Combine like terms: 1 + -1 = 0
24z = 0 + 24z
24z = 24z

Add '-24z' to each side of the equation.
24z + -24z = 24z + -24z

Combine like terms: 24z + -24z = 0
0 = 24z + -24z

Combine like terms: 24z + -24z = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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