3(8j-1-)=5(7j+5)

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Solution for 3(8j-1-)=5(7j+5) equation: 



3(8j-1-)=5(7j+5)

We move all terms to the left:

3(8j-1-)-(5(7j+5))=0

We add all the numbers together, and all the variables

3(+8j)-(5(7j+5))=0

We multiply parentheses

24j-(5(7j+5))=0



We calculate terms in parentheses: -(5(7j+5)), so:

5(7j+5)

We multiply parentheses

35j+25

Back to the equation:

-(35j+25)



We get rid of parentheses

24j-35j-25=0

We add all the numbers together, and all the variables

-11j-25=0

We move all terms containing j to the left, all other terms to the right

-11j=25

j=25/-11

j=-2+3/11

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