3(8-2x)+6=4x+40

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Solution for 3(8-2x)+6=4x+40 equation: 



3(8-2x)+6=4x+40

We move all terms to the left:

3(8-2x)+6-(4x+40)=0

We add all the numbers together, and all the variables

3(-2x+8)-(4x+40)+6=0

We multiply parentheses

-6x-(4x+40)+24+6=0

We get rid of parentheses

-6x-4x-40+24+6=0

We add all the numbers together, and all the variables

-10x-10=0

We move all terms containing x to the left, all other terms to the right

-10x=10

x=10/-10

x=-1

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