3(7y-1)-(3y-5)-25=4(y+3)-7

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Solution for 3(7y-1)-(3y-5)-25=4(y+3)-7 equation: 



3(7y-1)-(3y-5)-25=4(y+3)-7

We move all terms to the left:

3(7y-1)-(3y-5)-25-(4(y+3)-7)=0

We multiply parentheses

21y-(3y-5)-(4(y+3)-7)-3-25=0

We get rid of parentheses

21y-3y-(4(y+3)-7)+5-3-25=0



We calculate terms in parentheses: -(4(y+3)-7), so:

4(y+3)-7

We multiply parentheses

4y+12-7

We add all the numbers together, and all the variables

4y+5

Back to the equation:

-(4y+5)



We add all the numbers together, and all the variables

18y-(4y+5)-23=0

We get rid of parentheses

18y-4y-5-23=0

We add all the numbers together, and all the variables

14y-28=0

We move all terms containing y to the left, all other terms to the right

14y=28

y=28/14

y=2

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