3(7x2)=27

Solution for 3(7x2)=27 equation:

3(7x^2)=27

We move all terms to the left:

3(7x^2)-(27)=0

a = 37; b = 0; c = -27;
Δ = b2-4ac
Δ = 02-4·37·(-27)
Δ = 3996
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3996}=\sqrt{36*111}=\sqrt{36}*\sqrt{111}=6\sqrt{111}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{111}}{2*37}=\frac{0-6\sqrt{111}}{74}
=-\frac{6\sqrt{111}}{74}
=-\frac{3\sqrt{111}}{37}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{111}}{2*37}=\frac{0+6\sqrt{111}}{74}
=\frac{6\sqrt{111}}{74}
=\frac{3\sqrt{111}}{37}
$