3(7x-5)+12x=5(5x+1)+8x-20

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Solution for 3(7x-5)+12x=5(5x+1)+8x-20 equation: 



3(7x-5)+12x=5(5x+1)+8x-20

We move all terms to the left:

3(7x-5)+12x-(5(5x+1)+8x-20)=0

We add all the numbers together, and all the variables

12x+3(7x-5)-(5(5x+1)+8x-20)=0

We multiply parentheses

12x+21x-(5(5x+1)+8x-20)-15=0



We calculate terms in parentheses: -(5(5x+1)+8x-20), so:

5(5x+1)+8x-20

We add all the numbers together, and all the variables

8x+5(5x+1)-20

We multiply parentheses

8x+25x+5-20

We add all the numbers together, and all the variables

33x-15

Back to the equation:

-(33x-15)



We add all the numbers together, and all the variables

33x-(33x-15)-15=0

We get rid of parentheses

33x-33x+15-15=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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