3(7x-4)=3(6x+1)

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Solution for 3(7x-4)=3(6x+1) equation: 



3(7x-4)=3(6x+1)

We move all terms to the left:

3(7x-4)-(3(6x+1))=0

We multiply parentheses

21x-(3(6x+1))-12=0



We calculate terms in parentheses: -(3(6x+1)), so:

3(6x+1)

We multiply parentheses

18x+3

Back to the equation:

-(18x+3)



We get rid of parentheses

21x-18x-3-12=0

We add all the numbers together, and all the variables

3x-15=0

We move all terms containing x to the left, all other terms to the right

3x=15

x=15/3

x=5

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