3(7x+20)=5(4x-3)+30

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Solution for 3(7x+20)=5(4x-3)+30 equation: 



3(7x+20)=5(4x-3)+30

We move all terms to the left:

3(7x+20)-(5(4x-3)+30)=0

We multiply parentheses

21x-(5(4x-3)+30)+60=0



We calculate terms in parentheses: -(5(4x-3)+30), so:

5(4x-3)+30

We multiply parentheses

20x-15+30

We add all the numbers together, and all the variables

20x+15

Back to the equation:

-(20x+15)



We get rid of parentheses

21x-20x-15+60=0

We add all the numbers together, and all the variables

x+45=0

We move all terms containing x to the left, all other terms to the right

x=-45

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