3(7x+1)=19x-7

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Solution for 3(7x+1)=19x-7 equation:



3(7x+1)=19x-7
We move all terms to the left:
3(7x+1)-(19x-7)=0
We multiply parentheses
21x-(19x-7)+3=0
We get rid of parentheses
21x-19x+7+3=0
We add all the numbers together, and all the variables
2x+10=0
We move all terms containing x to the left, all other terms to the right
2x=-10
x=-10/2
x=-5

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