3(7m+12)=2(m-3)

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Solution for 3(7m+12)=2(m-3) equation: 



3(7m+12)=2(m-3)

We move all terms to the left:

3(7m+12)-(2(m-3))=0

We multiply parentheses

21m-(2(m-3))+36=0



We calculate terms in parentheses: -(2(m-3)), so:

2(m-3)

We multiply parentheses

2m-6

Back to the equation:

-(2m-6)



We get rid of parentheses

21m-2m+6+36=0

We add all the numbers together, and all the variables

19m+42=0

We move all terms containing m to the left, all other terms to the right

19m=-42

m=-42/19

m=-2+4/19

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