3(7j+11)=6(6j+13)

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Solution for 3(7j+11)=6(6j+13) equation: 



3(7j+11)=6(6j+13)

We move all terms to the left:

3(7j+11)-(6(6j+13))=0

We multiply parentheses

21j-(6(6j+13))+33=0



We calculate terms in parentheses: -(6(6j+13)), so:

6(6j+13)

We multiply parentheses

36j+78

Back to the equation:

-(36j+78)



We get rid of parentheses

21j-36j-78+33=0

We add all the numbers together, and all the variables

-15j-45=0

We move all terms containing j to the left, all other terms to the right

-15j=45

j=45/-15

j=-3

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