3(7c+1)-35=14c+3

Solution for 3(7c+1)-35=14c+3 equation:

Simplifying
3(7c + 1) + -35 = 14c + 3

Reorder the terms:
3(1 + 7c) + -35 = 14c + 3
(1 * 3 + 7c * 3) + -35 = 14c + 3
(3 + 21c) + -35 = 14c + 3

Reorder the terms:
3 + -35 + 21c = 14c + 3

Combine like terms: 3 + -35 = -32
-32 + 21c = 14c + 3

Reorder the terms:
-32 + 21c = 3 + 14c

Solving
-32 + 21c = 3 + 14c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-14c' to each side of the equation.
-32 + 21c + -14c = 3 + 14c + -14c

Combine like terms: 21c + -14c = 7c
-32 + 7c = 3 + 14c + -14c

Combine like terms: 14c + -14c = 0
-32 + 7c = 3 + 0
-32 + 7c = 3

Add '32' to each side of the equation.
-32 + 32 + 7c = 3 + 32

Combine like terms: -32 + 32 = 0
0 + 7c = 3 + 32
7c = 3 + 32

Combine like terms: 3 + 32 = 35
7c = 35

Divide each side by '7'.
c = 5

Simplifying
c = 5