3(72)=6(16-4/5x)

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Solution for 3(72)=6(16-4/5x) equation: 



3(72)=6(16-4/5x)

We move all terms to the left:

3(72)-(6(16-4/5x))=0



Domain of the equation: 5x))!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

-(6(-4/5x+16))+372=0

We multiply all the terms by the denominator


-(6(-4+372*5x+16))=0



We calculate terms in parentheses: -(6(-4+372*5x+16)), so:

6(-4+372*5x+16)

We add all the numbers together, and all the variables

6(372*5x+12)

We multiply parentheses

11160x+72

Back to the equation:

-(11160x+72)



We get rid of parentheses

-11160x-72=0

We move all terms containing x to the left, all other terms to the right

-11160x=72

x=72/-11160

x=-1/155

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