3(7-9k)+23k=4k-(24-k

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Solution for 3(7-9k)+23k=4k-(24-k equation: 



3(7-9k)+23k=4k-(24-k

We move all terms to the left:

3(7-9k)+23k-(4k-(24-k)=0

We add all the numbers together, and all the variables

3(-9k+7)+23k-(4k-(-1k+24)=0

We add all the numbers together, and all the variables

23k+3(-9k+7)-(4k-(-1k+24)=0

We multiply parentheses

23k-27k-(4k-(-1k+24)+21=0

We add all the numbers together, and all the variables

-4k-(4k-(-1k+24)+21=0

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