3(7+6x)(9+2x)=(35+4x)(2+9x)

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Solution for 3(7+6x)(9+2x)=(35+4x)(2+9x) equation:



3(7+6x)(9+2x)=(35+4x)(2+9x)
We move all terms to the left:
3(7+6x)(9+2x)-((35+4x)(2+9x))=0
We add all the numbers together, and all the variables
3(6x+7)(2x+9)-((4x+35)(9x+2))=0
We multiply parentheses ..
3(+12x^2+54x+14x+63)-((4x+35)(9x+2))=0
We calculate terms in parentheses: -((4x+35)(9x+2)), so:
(4x+35)(9x+2)
We multiply parentheses ..
(+36x^2+8x+315x+70)
We get rid of parentheses
36x^2+8x+315x+70
We add all the numbers together, and all the variables
36x^2+323x+70
Back to the equation:
-(36x^2+323x+70)
We multiply parentheses
36x^2+162x+42x-(36x^2+323x+70)+189=0
We get rid of parentheses
36x^2-36x^2+162x+42x-323x-70+189=0
We add all the numbers together, and all the variables
-119x+119=0
We move all terms containing x to the left, all other terms to the right
-119x=-119
x=-119/-119
x=1

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