3(7+3n)=-6-2(n+3)

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Solution for 3(7+3n)=-6-2(n+3) equation: 



3(7+3n)=-6-2(n+3)

We move all terms to the left:

3(7+3n)-(-6-2(n+3))=0

We add all the numbers together, and all the variables

3(3n+7)-(-6-2(n+3))=0

We multiply parentheses

9n-(-6-2(n+3))+21=0



We calculate terms in parentheses: -(-6-2(n+3)), so:

-6-2(n+3)

determiningTheFunctionDomain
-2(n+3)-6

We multiply parentheses

-2n-6-6

We add all the numbers together, and all the variables

-2n-12

Back to the equation:

-(-2n-12)



We get rid of parentheses

9n+2n+12+21=0

We add all the numbers together, and all the variables

11n+33=0

We move all terms containing n to the left, all other terms to the right

11n=-33

n=-33/11

n=-3

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