3(7+2x)-12=4x-2(x-4)

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Solution for 3(7+2x)-12=4x-2(x-4) equation: 



3(7+2x)-12=4x-2(x-4)

We move all terms to the left:

3(7+2x)-12-(4x-2(x-4))=0

We add all the numbers together, and all the variables

3(2x+7)-(4x-2(x-4))-12=0

We multiply parentheses

6x-(4x-2(x-4))+21-12=0



We calculate terms in parentheses: -(4x-2(x-4)), so:

4x-2(x-4)

We multiply parentheses

4x-2x+8

We add all the numbers together, and all the variables

2x+8

Back to the equation:

-(2x+8)



We add all the numbers together, and all the variables

6x-(2x+8)+9=0

We get rid of parentheses

6x-2x-8+9=0

We add all the numbers together, and all the variables

4x+1=0

We move all terms containing x to the left, all other terms to the right

4x=-1

x=-1/4

x=-1/4

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