3(7+2x)+3=(5+x)-9(x+1)

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Solution for 3(7+2x)+3=(5+x)-9(x+1) equation: 



3(7+2x)+3=(5+x)-9(x+1)

We move all terms to the left:

3(7+2x)+3-((5+x)-9(x+1))=0

We add all the numbers together, and all the variables

3(2x+7)-((x+5)-9(x+1))+3=0

We multiply parentheses

6x-((x+5)-9(x+1))+21+3=0



We calculate terms in parentheses: -((x+5)-9(x+1)), so:

(x+5)-9(x+1)

We multiply parentheses

(x+5)-9x-9

We get rid of parentheses

x-9x+5-9

We add all the numbers together, and all the variables

-8x-4

Back to the equation:

-(-8x-4)



We add all the numbers together, and all the variables

6x-(-8x-4)+24=0

We get rid of parentheses

6x+8x+4+24=0

We add all the numbers together, and all the variables

14x+28=0

We move all terms containing x to the left, all other terms to the right

14x=-28

x=-28/14

x=-2

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