3(7*0+2)+4*0=5(5*0+o.4)+4

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Solution for 3(7*0+2)+4*0=5(5*0+o.4)+4 equation: 



3(7*0+2)+4*0=5(5*0+o.4)+4

We move all terms to the left:

3(7*0+2)+4*0-(5(5*0+o.4)+4)=0

We add all the numbers together, and all the variables

-(5(+o.4)+4)+32+4*0=0

We add all the numbers together, and all the variables

-(5(+o.4)+4)+32=0



We calculate terms in parentheses: -(5(+o.4)+4), so:

5(+o.4)+4

We multiply parentheses

5o+4

Back to the equation:

-(5o+4)



We get rid of parentheses

-5o-4+32=0

We add all the numbers together, and all the variables

-5o+28=0

We move all terms containing o to the left, all other terms to the right

-5o=-28

o=-28/-5

o=5+3/5

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