3(6z-1)-4(z+1)=12(z+1)

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Solution for 3(6z-1)-4(z+1)=12(z+1) equation:


Simplifying
3(6z + -1) + -4(z + 1) = 12(z + 1)

Reorder the terms:
3(-1 + 6z) + -4(z + 1) = 12(z + 1)
(-1 * 3 + 6z * 3) + -4(z + 1) = 12(z + 1)
(-3 + 18z) + -4(z + 1) = 12(z + 1)

Reorder the terms:
-3 + 18z + -4(1 + z) = 12(z + 1)
-3 + 18z + (1 * -4 + z * -4) = 12(z + 1)
-3 + 18z + (-4 + -4z) = 12(z + 1)

Reorder the terms:
-3 + -4 + 18z + -4z = 12(z + 1)

Combine like terms: -3 + -4 = -7
-7 + 18z + -4z = 12(z + 1)

Combine like terms: 18z + -4z = 14z
-7 + 14z = 12(z + 1)

Reorder the terms:
-7 + 14z = 12(1 + z)
-7 + 14z = (1 * 12 + z * 12)
-7 + 14z = (12 + 12z)

Solving
-7 + 14z = 12 + 12z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-12z' to each side of the equation.
-7 + 14z + -12z = 12 + 12z + -12z

Combine like terms: 14z + -12z = 2z
-7 + 2z = 12 + 12z + -12z

Combine like terms: 12z + -12z = 0
-7 + 2z = 12 + 0
-7 + 2z = 12

Add '7' to each side of the equation.
-7 + 7 + 2z = 12 + 7

Combine like terms: -7 + 7 = 0
0 + 2z = 12 + 7
2z = 12 + 7

Combine like terms: 12 + 7 = 19
2z = 19

Divide each side by '2'.
z = 9.5

Simplifying
z = 9.5

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