3(6z-1)-2(z+9)=13(z+1)

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Solution for 3(6z-1)-2(z+9)=13(z+1) equation:


Simplifying
3(6z + -1) + -2(z + 9) = 13(z + 1)

Reorder the terms:
3(-1 + 6z) + -2(z + 9) = 13(z + 1)
(-1 * 3 + 6z * 3) + -2(z + 9) = 13(z + 1)
(-3 + 18z) + -2(z + 9) = 13(z + 1)

Reorder the terms:
-3 + 18z + -2(9 + z) = 13(z + 1)
-3 + 18z + (9 * -2 + z * -2) = 13(z + 1)
-3 + 18z + (-18 + -2z) = 13(z + 1)

Reorder the terms:
-3 + -18 + 18z + -2z = 13(z + 1)

Combine like terms: -3 + -18 = -21
-21 + 18z + -2z = 13(z + 1)

Combine like terms: 18z + -2z = 16z
-21 + 16z = 13(z + 1)

Reorder the terms:
-21 + 16z = 13(1 + z)
-21 + 16z = (1 * 13 + z * 13)
-21 + 16z = (13 + 13z)

Solving
-21 + 16z = 13 + 13z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-13z' to each side of the equation.
-21 + 16z + -13z = 13 + 13z + -13z

Combine like terms: 16z + -13z = 3z
-21 + 3z = 13 + 13z + -13z

Combine like terms: 13z + -13z = 0
-21 + 3z = 13 + 0
-21 + 3z = 13

Add '21' to each side of the equation.
-21 + 21 + 3z = 13 + 21

Combine like terms: -21 + 21 = 0
0 + 3z = 13 + 21
3z = 13 + 21

Combine like terms: 13 + 21 = 34
3z = 34

Divide each side by '3'.
z = 11.33333333

Simplifying
z = 11.33333333

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