3(6z-1)-2(z+5)=12(z+1)

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Solution for 3(6z-1)-2(z+5)=12(z+1) equation:


Simplifying
3(6z + -1) + -2(z + 5) = 12(z + 1)

Reorder the terms:
3(-1 + 6z) + -2(z + 5) = 12(z + 1)
(-1 * 3 + 6z * 3) + -2(z + 5) = 12(z + 1)
(-3 + 18z) + -2(z + 5) = 12(z + 1)

Reorder the terms:
-3 + 18z + -2(5 + z) = 12(z + 1)
-3 + 18z + (5 * -2 + z * -2) = 12(z + 1)
-3 + 18z + (-10 + -2z) = 12(z + 1)

Reorder the terms:
-3 + -10 + 18z + -2z = 12(z + 1)

Combine like terms: -3 + -10 = -13
-13 + 18z + -2z = 12(z + 1)

Combine like terms: 18z + -2z = 16z
-13 + 16z = 12(z + 1)

Reorder the terms:
-13 + 16z = 12(1 + z)
-13 + 16z = (1 * 12 + z * 12)
-13 + 16z = (12 + 12z)

Solving
-13 + 16z = 12 + 12z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-12z' to each side of the equation.
-13 + 16z + -12z = 12 + 12z + -12z

Combine like terms: 16z + -12z = 4z
-13 + 4z = 12 + 12z + -12z

Combine like terms: 12z + -12z = 0
-13 + 4z = 12 + 0
-13 + 4z = 12

Add '13' to each side of the equation.
-13 + 13 + 4z = 12 + 13

Combine like terms: -13 + 13 = 0
0 + 4z = 12 + 13
4z = 12 + 13

Combine like terms: 12 + 13 = 25
4z = 25

Divide each side by '4'.
z = 6.25

Simplifying
z = 6.25

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