3(6z+3)=27

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Solution for 3(6z+3)=27 equation: 



3(6z+3)=27

We move all terms to the left:

3(6z+3)-(27)=0

We multiply parentheses

18z+9-27=0

We add all the numbers together, and all the variables

18z-18=0

We move all terms containing z to the left, all other terms to the right

18z=18

z=18/18

z=1

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