3(6z+2)=6(2z+2)

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Solution for 3(6z+2)=6(2z+2) equation: 



3(6z+2)=6(2z+2)

We move all terms to the left:

3(6z+2)-(6(2z+2))=0

We multiply parentheses

18z-(6(2z+2))+6=0



We calculate terms in parentheses: -(6(2z+2)), so:

6(2z+2)

We multiply parentheses

12z+12

Back to the equation:

-(12z+12)



We get rid of parentheses

18z-12z-12+6=0

We add all the numbers together, and all the variables

6z-6=0

We move all terms containing z to the left, all other terms to the right

6z=6

z=6/6

z=1

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