3(6x+4)=2(7x-36)

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Solution for 3(6x+4)=2(7x-36) equation:



3(6x+4)=2(7x-36)
We move all terms to the left:
3(6x+4)-(2(7x-36))=0
We multiply parentheses
18x-(2(7x-36))+12=0
We calculate terms in parentheses: -(2(7x-36)), so:
2(7x-36)
We multiply parentheses
14x-72
Back to the equation:
-(14x-72)
We get rid of parentheses
18x-14x+72+12=0
We add all the numbers together, and all the variables
4x+84=0
We move all terms containing x to the left, all other terms to the right
4x=-84
x=-84/4
x=-21

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