3(6x+4)-18=3(2x+10)

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Solution for 3(6x+4)-18=3(2x+10) equation: 



3(6x+4)-18=3(2x+10)

We move all terms to the left:

3(6x+4)-18-(3(2x+10))=0

We multiply parentheses

18x-(3(2x+10))+12-18=0



We calculate terms in parentheses: -(3(2x+10)), so:

3(2x+10)

We multiply parentheses

6x+30

Back to the equation:

-(6x+30)



We add all the numbers together, and all the variables

18x-(6x+30)-6=0

We get rid of parentheses

18x-6x-30-6=0

We add all the numbers together, and all the variables

12x-36=0

We move all terms containing x to the left, all other terms to the right

12x=36

x=36/12

x=3

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