3(6t+1)-11=t-(t+7)

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Solution for 3(6t+1)-11=t-(t+7) equation: 



3(6t+1)-11=t-(t+7)

We move all terms to the left:

3(6t+1)-11-(t-(t+7))=0

We multiply parentheses

18t-(t-(t+7))+3-11=0



We calculate terms in parentheses: -(t-(t+7)), so:

t-(t+7)

We get rid of parentheses

t-t-7

We add all the numbers together, and all the variables

-7

Back to the equation:

-(-7)



We add all the numbers together, and all the variables

18t-1=0

We move all terms containing t to the left, all other terms to the right

18t=1

t=1/18

t=1/18

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