3(6r-5)+2r=3(r+5)-5r

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Solution for 3(6r-5)+2r=3(r+5)-5r equation: 



3(6r-5)+2r=3(r+5)-5r

We move all terms to the left:

3(6r-5)+2r-(3(r+5)-5r)=0

We add all the numbers together, and all the variables

2r+3(6r-5)-(3(r+5)-5r)=0

We multiply parentheses

2r+18r-(3(r+5)-5r)-15=0



We calculate terms in parentheses: -(3(r+5)-5r), so:

3(r+5)-5r

We add all the numbers together, and all the variables

-5r+3(r+5)

We multiply parentheses

-5r+3r+15

We add all the numbers together, and all the variables

-2r+15

Back to the equation:

-(-2r+15)



We add all the numbers together, and all the variables

20r-(-2r+15)-15=0

We get rid of parentheses

20r+2r-15-15=0

We add all the numbers together, and all the variables

22r-30=0

We move all terms containing r to the left, all other terms to the right

22r=30

r=30/22

r=1+4/11

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