3(6-z)-26=17z-4(2+5z)

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Solution for 3(6-z)-26=17z-4(2+5z) equation:


Simplifying
3(6 + -1z) + -26 = 17z + -4(2 + 5z)
(6 * 3 + -1z * 3) + -26 = 17z + -4(2 + 5z)
(18 + -3z) + -26 = 17z + -4(2 + 5z)

Reorder the terms:
18 + -26 + -3z = 17z + -4(2 + 5z)

Combine like terms: 18 + -26 = -8
-8 + -3z = 17z + -4(2 + 5z)
-8 + -3z = 17z + (2 * -4 + 5z * -4)
-8 + -3z = 17z + (-8 + -20z)

Reorder the terms:
-8 + -3z = -8 + 17z + -20z

Combine like terms: 17z + -20z = -3z
-8 + -3z = -8 + -3z

Add '8' to each side of the equation.
-8 + 8 + -3z = -8 + 8 + -3z

Combine like terms: -8 + 8 = 0
0 + -3z = -8 + 8 + -3z
-3z = -8 + 8 + -3z

Combine like terms: -8 + 8 = 0
-3z = 0 + -3z
-3z = -3z

Add '3z' to each side of the equation.
-3z + 3z = -3z + 3z

Combine like terms: -3z + 3z = 0
0 = -3z + 3z

Combine like terms: -3z + 3z = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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