3(6+7y)=2(1-5y)=42

Solution for 3(6+7y)=2(1-5y)=42 equation:

3(6+7y)=2(1-5y)=42

We move all terms to the left:

3(6+7y)-(2(1-5y))=0

We add all the numbers together, and all the variables

3(7y+6)-(2(-5y+1))=0

We multiply parentheses

21y-(2(-5y+1))+18=0


We calculate terms in parentheses: -(2(-5y+1)), so:

2(-5y+1)

We multiply parentheses

-10y+2

Back to the equation:

-(-10y+2)


We get rid of parentheses

21y+10y-2+18=0

We add all the numbers together, and all the variables

31y+16=0

We move all terms containing y to the left, all other terms to the right

31y=-16

y=-16/31

y=-16/31