3(6+7y)+(2-5y)=42

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Solution for 3(6+7y)+(2-5y)=42 equation:



3(6+7y)+(2-5y)=42
We move all terms to the left:
3(6+7y)+(2-5y)-(42)=0
We add all the numbers together, and all the variables
3(7y+6)+(-5y+2)-42=0
We multiply parentheses
21y+(-5y+2)+18-42=0
We get rid of parentheses
21y-5y+2+18-42=0
We add all the numbers together, and all the variables
16y-22=0
We move all terms containing y to the left, all other terms to the right
16y=22
y=22/16
y=1+3/8

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