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3(6+5(y))=2(-5+4(y))
We move all terms to the left:
3(6+5(y))-(2(-5+4(y)))=0
We add all the numbers together, and all the variables
3(5y+6)-(2(4y-5))=0
We multiply parentheses
15y-(2(4y-5))+18=0
We calculate terms in parentheses: -(2(4y-5)), so:We get rid of parentheses
2(4y-5)
We multiply parentheses
8y-10
Back to the equation:
-(8y-10)
15y-8y+10+18=0
We add all the numbers together, and all the variables
7y+28=0
We move all terms containing y to the left, all other terms to the right
7y=-28
y=-28/7
y=-4
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