3(6+2m)=4(2m+12)

Solution for 3(6+2m)=4(2m+12) equation:

3(6+2m)=4(2m+12)

We move all terms to the left:

3(6+2m)-(4(2m+12))=0

We add all the numbers together, and all the variables

3(2m+6)-(4(2m+12))=0

We multiply parentheses

6m-(4(2m+12))+18=0


We calculate terms in parentheses: -(4(2m+12)), so:

4(2m+12)

We multiply parentheses

8m+48

Back to the equation:

-(8m+48)


We get rid of parentheses

6m-8m-48+18=0

We add all the numbers together, and all the variables

-2m-30=0

We move all terms containing m to the left, all other terms to the right

-2m=30

m=30/-2

m=-15