3(6+1)+4=2(y-1)+y+y

Solution for 3(6+1)+4=2(y-1)+y+y equation:

3(6+1)+4=2(y-1)+y+y

We move all terms to the left:

3(6+1)+4-(2(y-1)+y+y)=0

We add all the numbers together, and all the variables

-(2(y-1)+y+y)+4+37=0

We add all the numbers together, and all the variables

-(2(y-1)+y+y)+41=0


We calculate terms in parentheses: -(2(y-1)+y+y), so:

2(y-1)+y+y

We add all the numbers together, and all the variables

2y+2(y-1)

We multiply parentheses

2y+2y-2

We add all the numbers together, and all the variables

4y-2

Back to the equation:

-(4y-2)


We get rid of parentheses

-4y+2+41=0

We add all the numbers together, and all the variables

-4y+43=0

We move all terms containing y to the left, all other terms to the right

-4y=-43

y=-43/-4

y=10+3/4