3(5z-7)=-4(-10z+14)

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Solution for 3(5z-7)=-4(-10z+14) equation: 



3(5z-7)=-4(-10z+14)

We move all terms to the left:

3(5z-7)-(-4(-10z+14))=0

We multiply parentheses

15z-(-4(-10z+14))-21=0



We calculate terms in parentheses: -(-4(-10z+14)), so:

-4(-10z+14)

We multiply parentheses

40z-56

Back to the equation:

-(40z-56)



We get rid of parentheses

15z-40z+56-21=0

We add all the numbers together, and all the variables

-25z+35=0

We move all terms containing z to the left, all other terms to the right

-25z=-35

z=-35/-25

z=1+2/5

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