3(5z-7)-2(9z-11)=4(8z-13)

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Solution for 3(5z-7)-2(9z-11)=4(8z-13) equation: 



3(5z-7)-2(9z-11)=4(8z-13)

We move all terms to the left:

3(5z-7)-2(9z-11)-(4(8z-13))=0

We multiply parentheses

15z-18z-(4(8z-13))-21+22=0



We calculate terms in parentheses: -(4(8z-13)), so:

4(8z-13)

We multiply parentheses

32z-52

Back to the equation:

-(32z-52)



We add all the numbers together, and all the variables

-3z-(32z-52)+1=0

We get rid of parentheses

-3z-32z+52+1=0

We add all the numbers together, and all the variables

-35z+53=0

We move all terms containing z to the left, all other terms to the right

-35z=-53

z=-53/-35

z=1+18/35

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