3(5z-7)+2(9z-11)=4(8z-7)+11

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Solution for 3(5z-7)+2(9z-11)=4(8z-7)+11 equation: 



3(5z-7)+2(9z-11)=4(8z-7)+11

We move all terms to the left:

3(5z-7)+2(9z-11)-(4(8z-7)+11)=0

We multiply parentheses

15z+18z-(4(8z-7)+11)-21-22=0



We calculate terms in parentheses: -(4(8z-7)+11), so:

4(8z-7)+11

We multiply parentheses

32z-28+11

We add all the numbers together, and all the variables

32z-17

Back to the equation:

-(32z-17)



We add all the numbers together, and all the variables

33z-(32z-17)-43=0

We get rid of parentheses

33z-32z+17-43=0

We add all the numbers together, and all the variables

z-26=0

We move all terms containing z to the left, all other terms to the right

z=26

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