3(5z-1)-3(z+2)=4(z+1)

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Solution for 3(5z-1)-3(z+2)=4(z+1) equation:


Simplifying
3(5z + -1) + -3(z + 2) = 4(z + 1)

Reorder the terms:
3(-1 + 5z) + -3(z + 2) = 4(z + 1)
(-1 * 3 + 5z * 3) + -3(z + 2) = 4(z + 1)
(-3 + 15z) + -3(z + 2) = 4(z + 1)

Reorder the terms:
-3 + 15z + -3(2 + z) = 4(z + 1)
-3 + 15z + (2 * -3 + z * -3) = 4(z + 1)
-3 + 15z + (-6 + -3z) = 4(z + 1)

Reorder the terms:
-3 + -6 + 15z + -3z = 4(z + 1)

Combine like terms: -3 + -6 = -9
-9 + 15z + -3z = 4(z + 1)

Combine like terms: 15z + -3z = 12z
-9 + 12z = 4(z + 1)

Reorder the terms:
-9 + 12z = 4(1 + z)
-9 + 12z = (1 * 4 + z * 4)
-9 + 12z = (4 + 4z)

Solving
-9 + 12z = 4 + 4z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-4z' to each side of the equation.
-9 + 12z + -4z = 4 + 4z + -4z

Combine like terms: 12z + -4z = 8z
-9 + 8z = 4 + 4z + -4z

Combine like terms: 4z + -4z = 0
-9 + 8z = 4 + 0
-9 + 8z = 4

Add '9' to each side of the equation.
-9 + 9 + 8z = 4 + 9

Combine like terms: -9 + 9 = 0
0 + 8z = 4 + 9
8z = 4 + 9

Combine like terms: 4 + 9 = 13
8z = 13

Divide each side by '8'.
z = 1.625

Simplifying
z = 1.625

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