3(5z-1)-2(z+3)=4(z+1)

Solution for 3(5z-1)-2(z+3)=4(z+1) equation:

Simplifying
3(5z + -1) + -2(z + 3) = 4(z + 1)

Reorder the terms:
3(-1 + 5z) + -2(z + 3) = 4(z + 1)
(-1 * 3 + 5z * 3) + -2(z + 3) = 4(z + 1)
(-3 + 15z) + -2(z + 3) = 4(z + 1)

Reorder the terms:
-3 + 15z + -2(3 + z) = 4(z + 1)
-3 + 15z + (3 * -2 + z * -2) = 4(z + 1)
-3 + 15z + (-6 + -2z) = 4(z + 1)

Reorder the terms:
-3 + -6 + 15z + -2z = 4(z + 1)

Combine like terms: -3 + -6 = -9
-9 + 15z + -2z = 4(z + 1)

Combine like terms: 15z + -2z = 13z
-9 + 13z = 4(z + 1)

Reorder the terms:
-9 + 13z = 4(1 + z)
-9 + 13z = (1 * 4 + z * 4)
-9 + 13z = (4 + 4z)

Solving
-9 + 13z = 4 + 4z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-4z' to each side of the equation.
-9 + 13z + -4z = 4 + 4z + -4z

Combine like terms: 13z + -4z = 9z
-9 + 9z = 4 + 4z + -4z

Combine like terms: 4z + -4z = 0
-9 + 9z = 4 + 0
-9 + 9z = 4

Add '9' to each side of the equation.
-9 + 9 + 9z = 4 + 9

Combine like terms: -9 + 9 = 0
0 + 9z = 4 + 9
9z = 4 + 9

Combine like terms: 4 + 9 = 13
9z = 13

Divide each side by '9'.
z = 1.444444444

Simplifying
z = 1.444444444