3(5y-2)+2(3y+11)=28

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Solution for 3(5y-2)+2(3y+11)=28 equation: 



3(5y-2)+2(3y+11)=28

We move all terms to the left:

3(5y-2)+2(3y+11)-(28)=0

We multiply parentheses

15y+6y-6+22-28=0

We add all the numbers together, and all the variables

21y-12=0

We move all terms containing y to the left, all other terms to the right

21y=12

y=12/21

y=4/7

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